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I want to find the indices of col2 values other than a and group it together and put it in a list I could iterate over the rows and separate them myself, but maybe there's some simpler way using pandas functions. So the list will be having the indices of continuous occurred values other than a
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One situation in which it may be necessary is when comparing new data with existing data where only the categories are know, not the values of the continuous variable. I want to get all those group's, couldn't find any way to do it using dataframe.groupby or any other function You want to add a new column to your data frame that assigns each row to a category based on the values of a continuous column
Mutate() will return a modified copy of your data that includes the new column.
In this article, i’ll demonstrate how to group pandas dataframe by consecutive same values that repeat one or multiple times If you are still not quite sure what is the problem we’re trying to solve, don’t worry, you will understand by the sample data that is generated as follows: This function enables you to categorise any set of data into groups that you specify, for example ages into age groups Typically, a continuous variable might be divided into categories or groups.
Given a list, the goal is to create sublists where each contains only identical consecutive elements For example, with a = [4, 4, 5, 5, 5, 7, 7, 8, 8, 8], the result would be [ [4, 4], [5, 5, 5], [7, 7], [8, 8, 8]], as identical elements are grouped based on their occurrence sequence.
